the angle made by the straight line with the positive x axis in the positive direction and the y intercept cut off by it are given below. find the equation of the straight line
(i) 60 deg,3
(ii) 150 deg,2
Answers
Answer:
(i) √3x-y+3=0
(ii) x+y-2√3=0
Step-by-step explanation:
(i) formula used=
y=mx+c where c= 3, m=tan60
= tan60 =√3,
= y=√3x+3,
=√3x-y+3=0
(ii) similarly like first one u can try the second one taking c=2 and m=tan150
HINT: tan 150= tan(180-30)
= -tan30
Given : the angle made by the straight line with the positive x axis in the positive direction and the y intercept cut off by it are given
(i) 60 deg,3
(ii) 150 deg,2
To Find : Equation of line
Solution:
y = mx + c
is slope intercept form
c is y intercept
m = slope = tanθ where θ is the angle made by the straight line with the positive x axis in the positive direction
(i) 60 deg,3
m = tan60° = √3
c = 3
y = √3x + 3
(ii) 150 deg,2
m = tan150° = -1/√3
c = 2
=> y = -x/√3 + 2
=> √3y = -x + 2√3
=> x + √3y = 2√3
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