Question

The angle made by the vector A=i^+j^ with X axis is. ​

Answer 1

Hi there,

A = i + j

Magnitude of vertical component along y-axis = Magnitude of horizontal component along x-axis

Tanθ = Vertical component / Horizontal component

Tanθ = 1

θ = 45°

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Answer 2

Answer:

I+j

Explanation:

|A|=√AX2+AY2

|A|=√2

cos theta=1/√2

theta =45°