Question

the angle made by the vector A=i+j with x-axis is

Answer 1

Answer: 45°

Explanation:
A = i + j

Magnitude of vertical component along y-axis = Magnitude of horizontal component along x-axis

Tanθ = Vertical component / Horizontal component
Tanθ = 1
θ = 45°

Answer 2

Answer:

The angle made by the given vector will be 45°

Solution:

Given vector $A= i + j$

From a general form of vector written as vector $V = xi + yj$, when the given vector $A= i + j$ is compared,  

We get,  

x = 1  

and  

y = 1

And we know,  

$\tan \theta = \frac { y } { x }$

where θ is the angle made by the vector with x axis.

$\begin{array} { l } { \tan \theta = \frac { 1 } { 1 } } \\\\ { \tan \theta = 1 } \\\\ { \tan \theta = \tan 45 ^ { \circ } } \\\\ { \theta = 45 ^ { \circ } } \end{array}$

Hence, the angle (θ) made by the vector $A = i + j$ with the x-axis is 45°.