The angle of a cyclic quadreidctercel ABCD a
LA = (6x +10)° , LB=(5x)°
LC= (x+y)° , LD =(3y-10)°
Find x andy, and hence the value
of the four angles :
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Answer:
x=20,y=30
Step-by-step explanation:
in a cyclic quadrilateral opposite angles add up-to 180
so 6x+10+x+y=180
7x+y=170---eq1
and 5x+3y-10=180
5x+3y=190---eq2
solve eq1 and 2
21x+3y=510
5x+3y=190
16x= 320
x= 320/16= 20
7*20+y=170
140+y=170
y=30
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