Question

The angle of a hexagon 6x° , 4x° , 5x° , 6x° , 7x° and 8x°
find the value of x and the angle of hexagon

Answer 1

Answer:

Sum of all interior angles of a polygon of n sides = $(n-2)*180$

Thus, sum of all interior angles of hexagon,

$(6-2)*180\\=4*180\\=720\ degrees$ or 720°.

$=>6x+4x+5x+6x+7x+8x=720\\=>36x=720\\=>x=\frac{720}{36}= 20\ degrees$or 20°.

∴ ∠1 = 6x = 120°

∠2 = 4x = 80°

∠3 = 5x = 100°

∠4 = 6x = 120°

∠5 = 7x = 140°

∠6 = 8x = 160°

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Answer 2

Sum of the angles of a hexagon is 720°.

So,

6x° + 4x° + 5x° + 6x° + 7x° + 8x° = 720°

36x = 720

x = 20°

ANGLES OF THE HEXAGON ARE AS FOLLOWS:-

6x = 120°

6x = 120°

4x = 80°

5x = 100°

7x = 140°

8x = 160°