Math, asked by 7081960p, 4 months ago

the angle of a Pentagon are x,x-10,x+20 ,2x-44 and 2x-70 calculate x And all the angles​

Answers

Answered by thegenius7183
7

Answer:

92°, 82°, 112°, 140°, 114°

Step-by-step explanation:

formula to calculate sum of interior angles of Pentagon= (n-2)180 (n= no of sides)

a Pentagon has 5 sides so sum of interior angle of polygon=

(5-2) ×180 = 3×180 = 540°

so, x+(x-10)+(x+20)+(2x-44)+(2x-70) = 540

= x+x+x+2x+2x -10+20-44-70 = 540

= 7x-104 = 540

= 7x = 540+104

= 7x = 644

= x= 644/7 = 92°

so value of x = 92°

therefore, first angle = x = 92°

therefore, first angle = x = 92°second angle= x-10 = 92-10 = 82°

therefore, first angle = x = 92°second angle= x-10 = 92-10 = 82°third angle= x+20 = 92+20 = 112°

fourth angle= 2x-44 = 2(92)-44 = 184-44 = 140°

fourth angle= 2x-44 = 2(92)-44 = 184-44 = 140°fifth angle = 2x-70 = 2(92)-70 = 184-70 = 114°

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