the angle of a quadrilateral ABCD taken in an order in the ratio of 3:7:6:4 then ABCD is a
a)kite
b) parallelogram
c) square
d) rhombus
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Step-by-step explanation:
Given ratio of angles of quadrilateral ABCD is 3:7:6:4
Let the angles of quadrilateral ABCD be 3x,7x,6x,4x respectively.
We know that the sum of all amgles is 360°
∴x=18°
i.e, ∠A=3x=54° ∠C=6x=108°
∠B=7x=126° ∠D=4x=72°
⇒∠BCE=∠ADC=72°
Since the corresponding angles are equal,
BC∥AD
∴ Sum of interior angles
⇒∠A+∠B=126°+54°=180°
⇒∠C+∠D=108°+72°=180°
∴ ABCD is a trapezium.
Hence, the answer is trapezium.
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