the angle of a quadrilateral are 2x+10, 4x-10,3x-2o, 5x-40 .show that the quadrilateral is a parellogram
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paralelogram
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Step-by-step explanation:
If ABCD is a quadrilateral, then
(2x + 10)° + (4x - 10)° + (3x - 20)° + (5x - 40)° = 360°
14x - 60 = 360
14x = 420
x = 30°
m∠A = 2x + 10 = 70°
m∠B = 4x - 10 = 110°
m∠C = 3x - 20 = 70°
m∠D = 5x - 40 = 110°
A quadrilateral is a parallelogram if and only if two pairs of opposite angles are equal in measure.
m∠A = m∠C = 70° and m∠B = m∠D = 110°
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