Question

The angle of a quadrilateral are in



a.P the greatest angle is double the smallest angle find the four angle

Answer 1

Let the least angle be x. And the common difference is D. Then the four angles will be

x, x+d, x+2d, x+3d.

Now by property of quadrilaterals, sum of all angles is 360 degrees, therefore,

x+ x+d+ x+2d+ x+3d = 360

=> 4x + 6d = 360 (divide equation by 2)

=> 2x + 3d = 180

By the given condition,

x+3d (greatest angle) = 2 * x(smallest angle)

=> x + 3d = 2x

=> 3d = x

put this in above equation,

2x + x = 180

=> x = 60 degrees.

Now solving equation 3d = x by putting x = 60

d = 20

•Thus the four angles are

60, 80, 100, 120