The angle of a quadrilateral are in the ratio1:2;3:4. Find each angle
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Answered by
1
let the rate be x
we know that the, total sum of the angles in a quadrilateral =360°
thus,
1x+2x+3x+4x=360°
10x=360°
x=360/10
x=36°
therefore,
2x=2×36
=72°
3x=3×36
=108°
4x=4×36
=144°
hence, the angles are 36°,72°,108°,144°
verification -
sum of all angles in a quadrilateral=360°
thus,
36°+72°+108°+144°=360°
360°=360°
we know that the, total sum of the angles in a quadrilateral =360°
thus,
1x+2x+3x+4x=360°
10x=360°
x=360/10
x=36°
therefore,
2x=2×36
=72°
3x=3×36
=108°
4x=4×36
=144°
hence, the angles are 36°,72°,108°,144°
verification -
sum of all angles in a quadrilateral=360°
thus,
36°+72°+108°+144°=360°
360°=360°
Answered by
0
Answer:
Step-by-step explanation:
Let angle a =x ,b=2x,c=3x,d=4x .So,. Angle a+angle b +angle c+ angle d=360°. x+2x+3x+4x=360°. 10 x=360° x=36°. So,angle a=36°,b=72°,c=108°,d=144°
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