Question

The angle of a
quadrilateral
are
x, (x-10), (x+30) and 2x
angle of a
Find the angle
​

Answer 1

Step-by-step explanation:

let,

A be x

B be x-10

C be x+30

and D be 2x

we know the sum of all the angles of a quadrilateral is 360degree

so,A+B+C+D=360

=x+x-10+x+30+2x=360

=2x-10+30+2x=360

=2x-40+2x=360

=4x=360+40

=4x=400

=x=400/4

=x=100

therefore

A=100°

B=100-10=90

C=100+30=130

D=2(100)=200

Thanks

hope it helps

pls mark brainliest

Answer 2

Answer:

required angles are 68°, 58°,98°, 136°

Step-by-step explanation:

The angle of a quadrilateral are

x, (x-10), (x+30) and 2x

sum of angles of a quadrilateral= 360°

x + (x-10) + (x+30) + 2x= 360°

5x+ 20°= 360°

5x= 360°-20°

5x = 340

X = 340°/5

X = 68°

X -10°= 68°-10°=58°

X +30°= 68°+30°=98°

2 X = 2×68°= 136°

required angles are 68°, 58°,98°, 136°