Question

the angle of a triangle are (2 x + 6) (3 x + 18) and 5 x minus 24 (find x and the three angles​

Answer 1

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given :-

let the ∆ABC in which...

• Ang.A = 2x+6
• Ang.B = 3x+18
• Ang.C = 5x-24

in ∆ABC

ang.A + Ang.B + Ang.C = 180 ( sum of all angles of a ∆ is 180°)

=> 2x+6 + 3x+18 + 5x-24 = 180°

=> 2x + 3x + 5x + 6 + 18 - 24 = 180°

=> 10x + 24 - 24 = 180°

=> 10x = 180°

=> x = 18°

$now \: put \: the \: value \: of \: x \: \\ in \: given \: angles$

-1) Ang.A = 2x+6

=> Ang.A = 2(18)+6

=> Ang.A = 42°

-2) Ang.B = 3x+18

=> Ang.B = 3(18)+18

=> Ang B = 72°

-3) Ang.C = 5x-24

=> Ang.C = 5(18)-24

=> Ang.C = 66°

hence, the value of x = 18

and angles of triangle are 42°,72°and 66°

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