Question

the angle of a triangle are 3x,2x+60° & 5x-40°.find each angle.​

Answer 1

Answer:

The Correct Answer is mentioned below

Step-by-step explanation:

The angle sum property of a triangle says that the sum of its interior angles is equal to 180°. Whether a triangle is an acute, obtuse, or a right triangle, the sum of the angles will always be 180°. This can be represented as follows: In a triangle ABC, ∠A + ∠B + ∠C = 180°.

3x + 2x + 60 + 5x - 40 = 180

5x + 60 + 5x -40 = 180

10x + 60 - 40 = 180

10x + 20 = 180

10x = 180 - 20

10x = 160

x = 16

The first angle is = 3x = 3 X 16 = 48 Degrees

The Second angle is = 2x + 60 = 2 X 16 + 60 = 92 Degrees

The Third angle is = 5x - 40 = 5 X 16 - 40 = 40 Degrees

Answer 2

Given: The angles of a triangle are $3x,2x+60$°, $\ and\ 5x-40$°.

We have to find each angle.

As we know that a triangle's angles add up to 180 degrees because one exterior angle is equal to the sum of the other two angles in the triangle.

We are solving in the following way:

We have,

The angles of a triangle are $3x,2x+60$°, $\ and\ 5x-40$°

Now, from the above statement we can write:

$3x+2x+60+5x-40=180$

Solving the above equation further we get,

$\Rightarrow 3x+2x+60+5x-40=180\\\Rightarrow 10x+20=180\\\Rightarrow 10x=180-20\\\Rightarrow10x=160\\\\\Rightarrow x=\frac{160}{10} \\\\\Rightarrow x=16$

So, the angles of a triangle are:

$\Rightarrow 3x\Rightarrow3\times16\Rightarrow48\\\Rightarrow 2x+60 \Rightarrow 2\times16+60\Rightarrow92\\\Rightarrow 5x-40\Rightarrow5\times16-40\Rightarrow 40$

Hence, each angle of a triangle will be$48$°,$92$°, and$40$°.