Question

The angle of a triangle are given below, find them. 2xt10 x-5 4x+20

Answer 1

Answer:

We know that sum of all angles of a triangle is equal to 180°

So, (x+10)° + (2x-30)° + (x) ° = 180°

=> (x+2x+x)° + (10-30)° = 180°

=> (4x)° - 20° = 180°

=> 4x = 200

=> x=50 Ans

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Answer 2

Answer:

Angle= (2x-10),(x-5),(4x+20)

According to angle sum property in a Δ,

=> 2x-10+x-5+4x+20=180°

=> 7x + 5=180°

=> 7x = 180 - 5

=> 7x = 175

=> x = 175/7 = 25

Angle A= 2x - 10= 2×25-10= 40°.

Angle B= x -5= 25-5 = 20°.

Angle C= 4x + 20= 4×25+20= 120°.

Step-by-step explanation:

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