Question

The angle of a triangle are in A.P. the biggest angle is 105 degree .find all the angles in radians

Answer 1

Answer:

15°, 60° and 105°

Step-by-step explanation:

Since the angles are in A.P. and the sum of angles in a triangle = 180, we can say that the middle term = 180/3 = 60°.

And given biggest angle = 105°

So the smallest angle = 180 - 60 - 105 = 15°

So the angles are 15°, 60° and 105°, which are in A.P. with first term 15 and common difference 45

Answer 2

Answer :-

π/3 , 7π/ 12 , π/18

Given :-

Biggest angle = 105°

Solution:-

Let the angle of triangle in A.P be

a , a + d and a - d.

Sum of angle of a triangle is 180°

Now ,

→ a + a + d + a - d = 180 °

→ 3a = 180°

→ a = 60°

Now , It is given that biggest angle is 105° .

$\therefore$ a + d = 105

→ 60 + d = 105

→ d = 105 - 60

→ d = 45

Now ,

a = 60° = π / 3

a + d = 105 ° = 7π / 12

a - d = 60 - 45 = 15° = π / 18