The angle of a triangle are in A.P the smallest angle is 39 degree show that the triangle is a right triangle
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1
Hey,sup!
There are 3 Angles in a triangle and the sum of angles is 180°.
Let the angles in AP be 39°,39°+d and 39°+2d.
As per the question,
39°+39°+d+39°+2d=180°.
=>117°+3d=180°.
=>3d=180°-117°.
=>3d=63°.
=>d=63°/3= 21°.
So the angles are 39°.
39°+d = 39°+21°=60°.
39°+2d=39°+2*21°=39°+42°=81°.
So the angles in AP are 39°,60°,81°.
This is not a right angle triangle.
Hope it helps.
There are 3 Angles in a triangle and the sum of angles is 180°.
Let the angles in AP be 39°,39°+d and 39°+2d.
As per the question,
39°+39°+d+39°+2d=180°.
=>117°+3d=180°.
=>3d=180°-117°.
=>3d=63°.
=>d=63°/3= 21°.
So the angles are 39°.
39°+d = 39°+21°=60°.
39°+2d=39°+2*21°=39°+42°=81°.
So the angles in AP are 39°,60°,81°.
This is not a right angle triangle.
Hope it helps.
kushanaanandp4ac8a:
What!? I missed something
Answered by
0
♧♧HERE IS YOUR ANSWER♧♧
Let, the angles of the triangle are :
(a - d), a and (a + d),
where d be common difference.
Given that :
(a - d) = 30°
We know that :
Sum of the angles of a triangle is 180°
=> (a - d) + a + (a + d) = 180
=> 3a = 180
=> a = 60
So, d = 30°
Hence the angles are :
30°, 60° and 90°.
Therefore, the triangle is a right-angled triangle.
NOTE : Considering the angle as 30°, I am giving you the answer.
♧♧HOPE THIS HELPS YOU♧♧
Let, the angles of the triangle are :
(a - d), a and (a + d),
where d be common difference.
Given that :
(a - d) = 30°
We know that :
Sum of the angles of a triangle is 180°
=> (a - d) + a + (a + d) = 180
=> 3a = 180
=> a = 60
So, d = 30°
Hence the angles are :
30°, 60° and 90°.
Therefore, the triangle is a right-angled triangle.
NOTE : Considering the angle as 30°, I am giving you the answer.
♧♧HOPE THIS HELPS YOU♧♧
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