The angle of a triangle are in ratio 1:3:5 find the measure of each of the angle
shivamkuwrs164:
let ratio quantity be x then angle be x, 3x,and 5x.... x +3x +5x=180 9x=180 ~x=20
Answers
Answered by
3
Hey Mate,
ATQ,
x + 3x + 5x = 180
9x = 180
x = 20
so angles are 20, 60, 100
hope this helps you out!
ATQ,
x + 3x + 5x = 180
9x = 180
x = 20
so angles are 20, 60, 100
hope this helps you out!
Answered by
5
Let us take the given ratio be 1x :3x : 5x
Their sum = 1x + 3 x + 5 x = 9x.
But angle sum of a triangle is 180°.
So,
ATQ,9x =180°
or x = 180°/9
Therefore x = 20°
1st angle = 1x = 20°
2nd angle = 3x = 3×20°=60°
3rd angle = 5x = 5 ×20° =100°
Their sum = 1x + 3 x + 5 x = 9x.
But angle sum of a triangle is 180°.
So,
ATQ,9x =180°
or x = 180°/9
Therefore x = 20°
1st angle = 1x = 20°
2nd angle = 3x = 3×20°=60°
3rd angle = 5x = 5 ×20° =100°
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