the angle of a triangle are( X + 10) (X + 40 )and (2 x-30 )find the value of x
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x+10+x+40+2x-30=180
4x+20=180
4x=180-20
x=160/4
x=40
so the value of x is 40
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4x+20=180
4x=180-20
x=160/4
x=40
so the value of x is 40
mark me as brainlist
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x+10+x+40+2x-30=180
4x+20=180
4x=180-20
4x=160
x=160/4
x=40
first angle40+10=50
second angle=40+40=80
third angle=80-30=50
4x+20=180
4x=180-20
4x=160
x=160/4
x=40
first angle40+10=50
second angle=40+40=80
third angle=80-30=50
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