the angle of a triangle are (X-20),(x-40) and (1/2x-20). find the value x
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Answered by
0
x-20+x-40+1/2x-20=180
5/2x-80=180
5/2x=260
5x=520
x=520/5
x=104
5/2x-80=180
5/2x=260
5x=520
x=520/5
x=104
Answered by
3
here your solution
##############
there are three angle
(x-20), (x-40), (X/2-20)
we know that
sum of all triangle = 180°
then
x-20 +x-40 + X/2 -20 = 180°
2x+X/2 -80 = 180°
5x/2 = 180° +80°
5x = 260× 2
X = (260×2) / 5
X = 52×2
X = 104°
➡(x-40) = (104-40) = 64°
➡(x-20)=( 104- 20 )=> 84°
➡(X/2 -20) =( 104/2 -20) => 52-20 =32°
hope it's helpful ✌☺
##############
there are three angle
(x-20), (x-40), (X/2-20)
we know that
sum of all triangle = 180°
then
x-20 +x-40 + X/2 -20 = 180°
2x+X/2 -80 = 180°
5x/2 = 180° +80°
5x = 260× 2
X = (260×2) / 5
X = 52×2
X = 104°
➡(x-40) = (104-40) = 64°
➡(x-20)=( 104- 20 )=> 84°
➡(X/2 -20) =( 104/2 -20) => 52-20 =32°
hope it's helpful ✌☺
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