The angle of a triangle are (x-40) (X-20) (Xby 2 -10) find the value of x and then find all angle.give the answer
jarolishana:
can you elaborate the third bracket....
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Sum of angles of a triangle is 180
![(x - 40) + (x - 20) + ( \frac{x}{2} - 10) = 180 \\ \frac{5x}{2} - 70 = 180 \\ x = 100 (x - 40) + (x - 20) + ( \frac{x}{2} - 10) = 180 \\ \frac{5x}{2} - 70 = 180 \\ x = 100](https://tex.z-dn.net/?f=%28x+-+40%29+%2B+%28x+-+20%29+%2B+%28+%5Cfrac%7Bx%7D%7B2%7D++-+10%29+%3D+180+%5C%5C++%5Cfrac%7B5x%7D%7B2%7D++-+70+%3D+180+%5C%5C+x+%3D+100)
Therefore angles are 60, 80, 40
Therefore angles are 60, 80, 40
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