The angle of an aeroplane from A on the ground is 60 degree. After 6 sec flight, the angle of elevation changes to 45 degree. If the aeroplane is flying at a height of 3000 m, find the speed of the plane.
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where is my answer
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Answer: speed= 1000(1-√3)/3 m/s
Step-by-step explanation:hey it's your answer
In Δabc
tan45°= p/b
tan45°= 3000/BC
1=3000/BC
BC= 3000m --------------------------1
In ΔDBE
tan60°=3000/BE
1/√3= 3000/BE
BE= 3000√3 ----------------------------------2
BC-BE = 3000-3000√3/6
= 3000(1-1√3)/6
= 1000(1-1√3)/3 m/s ANS
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