Question

The angle of banking e for a cyclist taking a curve
is given by tan (theta) =v^n/rg
where symbols have their
usual meaning. Then value of n is:​

Answer 1

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• $\color{red}{n=2}$

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Mass of cyclist + cycle =M

radius of curvature of the curved path =R

Angle of inclination from vertical=θ

acceleration due to gravity=g

velocity of cyclist =v

Let the normal force : N from the ground on to cyclist. Balance forces in horizontal and vertical directions.

Nsinθ = Mv²/R= centripetal force for the cyclist to move in a curve of radius R ---->eq. (1)

Ncosθ=Mg = weight balanced by normal reaction from ground ------>eq.(2)

SO divide equ 1 by equ 2

tanθ= v²÷Rg

Compairing with the equation tanθ=v²÷Rg as given in question

Required answer is n=2 ✓✓

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