Question

The angle of depression from the top of a tower 12m height, at a point on the ground is 30degrees. find the distance of the point from the top of the tower? ​

Answer 1

From the figure , we get

GIVEN :-

AB = Height of tower = 12 m

AC = Distance of point from tower = x m

Angle of depression ,

DAC = CAB = 30°

R.T.P :-

To find the distance of point from the top of the tower.

SOLUTION :-

We know that,

$\sin = \frac{opposite \: side}{hypotenuse}$

here opposite side = 12 m

hypotenuse = x

substitute sin 30° and all the values , we get

$\sin(30) = \frac{12}{x}$

we know that sin 30 ° = 1/2

$\frac{1}{2} = \frac{12}{x}$

$x = 12 \times 2 = 24$

Therefore the distance of point from the top of the tower is 24 m

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