The angle of depression from the top of a tower 40m high at a point on the ground is 30 degree find the distance of the point from the top of a tower
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Answered by
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Let AB be a tower and C be a point on a group.
Height of tower (AB) = 40m
Angle of depression = 30°
Tan 30° = P/B = AB/BC
1/✓3 = 40/BC
BC = 40✓3.
HENCE,
B IS 40 ✓3 METER AWAY FROM THE FOOT OF A TOWER
Height of tower (AB) = 40m
Angle of depression = 30°
Tan 30° = P/B = AB/BC
1/✓3 = 40/BC
BC = 40✓3.
HENCE,
B IS 40 ✓3 METER AWAY FROM THE FOOT OF A TOWER
Answered by
1
Let XY be a tower and C be a point on a ground
XY = 40m
Angle of depression = 30°
Tan 30° = P/B = XY/XC
1/✓3 = 40/XC
XC = 40✓3.
HENCE,
XC IS 40 ✓3 METER AWAY FROM THE FOOT OF A TOWER
XY = 40m
Angle of depression = 30°
Tan 30° = P/B = XY/XC
1/✓3 = 40/XC
XC = 40✓3.
HENCE,
XC IS 40 ✓3 METER AWAY FROM THE FOOT OF A TOWER
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