Question

The angle of depression from the top of tower ,12m. high at a point on the ground is 30° find the distance of the point from the top of the tower?

(from top of tower NOT BASE)

Answer 1

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Answer 2

Answer:

24 m

Step-by-step explanation:

Refer the attached image .

The height of the tower i.e. AB = 12 m

The angle of depression from the top of tower at a point on the ground is 30°

i.e. ∠ACB = 30°

Since we are asked to find the distance of the point from the top of the tower i.e. AC

So, in ΔABC, to find AC we will use trigonometric ratio

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

$sin 30^{\circ} = \frac{AB}{AC}$

$\frac{1}{2} = \frac{12}{AC}$

$AC = 12*2$

$AC = 24$

Thus the distance of the point from the top of the tower is 24 m