the angle of depression of a car parked on the road from top of a 150m high tower is 30° find the distance of the car from the tower
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Answer:
Given: Height =150 m
Angle of depression =30
o
Consider the diagram,
In ΔABC,
Let, distance of the car from tower BC=x m,
In ΔABC,tan30
o
=
AB
AC
So, tan30
o
=
3
1
Therefore, AC=150
3
So, distance between the tower and car is 150
3
m
Step-by-step explanation:
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