The angle of depression of a car parked on the road the top of a 150 m high tower is 30°. Find the distance of
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tan30° = ab / bc
ab is tower = 150
1 /√3 = ab / 150
ab = 150 ÷√3
( rationalizing the denominator )
we get 150÷√3 × √3 ×√3 = 50√3
the distance = 50 √3
ab is tower = 150
1 /√3 = ab / 150
ab = 150 ÷√3
( rationalizing the denominator )
we get 150÷√3 × √3 ×√3 = 50√3
the distance = 50 √3
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