Question

The angle of depression of a car standing on a ground from top of a 75 m tower is 30° the distance of the car from the base of the tower in metre is

Answer 1

Hence height of the tower =129.9m

Answer 2

Answer:

In the figure below,

AB denotes the tower of length 66 m and C denotes the position of car. thus, CB be the distance of the car and base of tower. and ∠C denotes the angle between car and top of tower  so,  ∠C=30°.

We have to find the length CB.

In Δ ABC ,

\tan C=\dfrac{\text{perpendicular}}{\text{base}}

\tan 30^{\circ}=\frac{AB}{CB}

\tan 30^{\circ}=\frac{66}{CB}

Also , by trigonometric table, \tan 30^{\circ}=\frac{1}{\sqrt{3}}

\frac{1}{\sqrt{3}}=\frac{66}{CB}

{CB}=66 \times {\sqrt{3}}

Also, value of {\sqrt{3}}=1.732

then, {CB}=66 \times 1.732

{CB}=114.312

Thus, the distance of a car from the base of the tower is 114.312 m.

Step-by-step explanation: