the angle of depression of a vehicle on the ground from the top of a tower is 60.if a vehicle is at a distance of 100 m away from the building,find the height of the tower.
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Answered by
2
Answer:
In right angle triangle
ABC
the
∠ACB=
30
0
(Angle of depression of a car) and the tower is
75 m
high
Let the distance of car from ground isx m
Then
tan30
0
=
BCAB
=
x
75
⇒
3
1
=
x
75
⇒x=75
3
Answered by
0
Answer:
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