Question

the angle of depression of an object from A 60 M high tower is 30° the distance of the object from the tower is what

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Answer 1

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let BC be the distance from the foot of the tower and AB be the height of the tower

in the triangle ABC

tan 30o = AB/BC

1/ root3 = 60/BC

BC = 60 root 3

ROOT 3 = 1.732

BC = 60(1.732)

therefore bc = 103.92 m = 104m

therefore the distance from foot of the tower is 104m

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Answer 2

Hope it will help you.