Question

the angle of depression of an object on the ground from a tower of height 90 m is 60', then the distance of object from the tower is:​

Answer 1

Answer:

Distance between point of observation and foot of tower = 20 m = BC

Angle of elevation of top of tower = 60° = θ

Height of tower H = AB

Now from fig ABC

ΔABC is a right angle triangle

Answer 2

Answer:

The above answer is correct so mark it brainliest :)

Step-by-step explanation: