the angle of depression of an object on the ground from the top of the building is high is. Find the distance of the object from the building.
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Step-by-step explanation:
Let BC be x metre and AB be v meter.
In ΔADB.
tan 60∘=ABBD
3=y20+x
In ΔABC
tan 30∘=ABBC
31=yx
y=x3
Putting the value of r in equation (1)
3=x320+x
3x = 20 + x
2x = 20 ⇒ x = 10 m
Height of the tree 20 + 10 = 30 m.
Distance between point and foot of the tree
= 330=103 m
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