Question

the angle of depression of an object on the ground from the top of the building is 18m high is 60⁰. find the distance of the object from the building.​

Answer 1

Answer:

angle of depression = angle of elevation = 60⁰ [formula]

tan( 60 ) = $\frac{18}{distance of object from building}$  [ tan(x) = $\frac{opposite}{hypotenuse}$ ]

distance of the object from the building = $\frac{18}{tan( 60) }$ = 56.2m (3sf)