Question

The angle of depression of car parked on the road form the top of a 150m high tower is 30 Find the distance of the car from the tower.

Answer 1

hope this answer help u

Answer 2

Answer:

$\red { Distance \:of \: the \: car \: from \: the}$

$\red { tower = AB}\green {= 259.8 \: m}$

Step-by-step explanation:

$Hight \: of \: the \: tower (BC) = 150\:m$

$Angle \: of \: depression (x) = 30\degree$

$\angle A = \angle x = 30\degree$

$Distance \:of \: the \: car \: from \: the \: tower = AB$

$In \: \triangle ABC = 90\degree$

$tan 30\degree = \frac{BC}{AB}$

$\implies \frac{1}{\sqrt{3}} = \frac{150}{AB}$

$\implies AB = 150\sqrt{3}$

$\implies AB = 150\times 1.732$

$\implies AB = 259.8 \:m$

Therefore.,

$\red { Distance \:of \: the \: car \: from \: the}$

$\red { tower = AB}\green {= 259.8 \: m}$

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