Question

The angle of depression of car parked on the road from the top of a 150m high tower is 30°. Find the distance of the car from the tower?​

Answer 1

Given: Height =150 m

Given: Height =150 mAngle of depression =30

Consider the diagram,

Consider the diagram,In ΔABC,

Let, distance of the car from tower BC=x m,

In ΔABC, tan30 = AC / AB

So, tan30 = 1 / √3

Therefore, AC=150√3

So, distance between the tower and car is 150√3 m