Question

the angle of depression of car parked on the road from the top of a 250 I Tower is 30 degree find the distance of the car from the tower​

Answer 1

Given: Height of Tower =150 m

Given: Height of Tower =150 mAngle of depression = 30

Given: Height of Tower =150 mAngle of depression = 30 ∘

Given: Height of Tower =150 mAngle of depression = 30 ∘

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metres

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30 ∘

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30 ∘ = ABAC

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30 ∘ = ABAC

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30 ∘ = ABAC

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30 ∘ = ABAC 31= x150

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30 ∘ = ABAC 31= x150

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30 ∘ = ABAC 31= x150

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30 ∘ = ABAC 31= x150 x=150

Given: Height of Tower =150 mAngle of depression = 30 ∘ ∠DCB=30 ∘ ∠DCB=∠ABC (Alternate angles)Let, distance of car from tower AB be x metresIn △ABC,tan30 ∘ = ABAC 31= x150 x=150 3