Question

The angle of depression of the top and bottom of a 50m high building from the top of a

tower are 45° and 60° respectively. Find the height of the tower and the horizontal

distance betweenthe tower and the building. (use √3 = 1.73)​

Answer 1

Answer:

Here CD is the tower and AB is the pole.

In △CDB, CD/BC = tan 60°

=> 50m/BC = √3

=> BC = 50/√3m

AE = BC

AE = 50/√3m

In △ADE, DE/AE = tan 45°

=> DE/50/√3m = 1

=> DE = 50/√3m

so the height of the pole is 50/√3m