Question

the angle of depression of the top and bottom of a building 50 M high as observed from the top of a tower are 30° and 60° respectively find the height of the building and Tower​

Answer 1

tan 60 = 50/x

√3 = 50/x

x = 50/√3

tan 30 = p/b

1/√3 = 50-y/50/√3

1/√3 = √3/50(50-y)

on cross multiplication

50(50-y) = 3

2500-50y = 3

2500-3 = 50y

2497 = 50y

2497/50 = y

49.94 = y

50 + 49.94 = 99.94 = building height

tower height 50 m