Physics, asked by Shakti6654, 9 months ago

The angle of dip,if dip needle oscillating in a vertical plane makes 40 oscillations/min. in a magnetic meridian & 30 oscillations/min in a vertical plane right angles to the magnetic meridian is

Answers

Answered by SUBRATA4322
0

Answer:

The angle of the dip, if a dip needle oscillating in a vertical plane makes 40 oscillations per minute in a magnetic meridian and 30 oscillations per minute in a vertical plane at right angle to the magnetic meridian, is:

A .

θ=sin−1(0.5625)

B .

θ=sin−1(0.325)

C .

θ=sin−1(0.425)

D .

θ=sin−1(0.235)

ANSWER

We have, 

ων=40/min

ωH=30/min

We know that,  tanθ=(ωνωH)2

tanθ=(4030)2

θ=tan−1(0.75)2

θ=tan−1(0.5625)

Answered by Agamsain
0

Answer:

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