The angle of dip,if dip needle oscillating in a vertical plane makes 40 oscillations/min. in a magnetic meridian & 30 oscillations/min in a vertical plane right angles to the magnetic meridian is
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The angle of the dip, if a dip needle oscillating in a vertical plane makes 40 oscillations per minute in a magnetic meridian and 30 oscillations per minute in a vertical plane at right angle to the magnetic meridian, is:
A .
θ=sin−1(0.5625)
B .
θ=sin−1(0.325)
C .
θ=sin−1(0.425)
D .
θ=sin−1(0.235)
ANSWER
We have,
ων=40/min
ωH=30/min
We know that, tanθ=(ωνωH)2
tanθ=(4030)2
θ=tan−1(0.75)2
θ=tan−1(0.5625)
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