Question

the angle of elevation at the top of a tower at a point on the ground 50m away from the tower is 50 degrees. then the height of the tower is​

Answer 1

Answer:

Let the height of the tower be h m.

From △PAB,tan30°=Ab/pa

1 upon 3 sqrt = h/50

h= 50/3sqroot

hence, the height of the tower is h= 50/3sqroot

Answer 2

Answer:

Let the height of the tower be h m.

From △PAB,tan30°=Ab/pa

1 upon 3 sqrt = h/50

h= 50/3sqroot

hence, the height of the tower is

h= 50/3sqroot