The angle of elevation from a point on the ground to the top of a tower is 18 degrees. The base of the tower is 100 feet from the point on the ground. Find the height of the tower. Round to the nearest tenth of a foot
Answers
Let the Height of the tower be x.
- The angle of elevation from a point on the ground to the top of a tower is 18⁰.
- Base of the tower is 100 feet
As We know that Angle (∅) b/w the point on ground and top of the tower is 18⁰.
→ tan ∅ = Perpendicular/Base
→ {(√5)-1}/√[10+2√5] = x/100
→ x = {(100√5)-100}/√[10+2√5]
→ x = 30 feet (approx.)
Hence,
The Height of the tower will be 30 Feet approximately.
Let the Height of the tower be x.
The angle of elevation from a point on the ground to the top of a tower is 18⁰.
Base of the tower is 100 feet
As We know that Angle (∅) b/w the point on ground and top of the tower is 18⁰.
→ tan ∅ = Perpendicular/Base
→ {(√5)-1}/√[10+2√5] = x/100
→ x = {(100√5)-100}/√[10+2√5]
→ x = 30 feet (approx.)
Hence,
The Height of the tower will be 30 Feet approximately.