Question

the angle of elevation from the top of a tower from the top of a ground which is 30m away from the foot of the tower is 30 degrees. what is the length of the tower

Answer 1

Step-by-step explanation:

In ∆ ABC,

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.