the angle of elevation from the top of the tower from a point on a ground which is 30 metres from the foot of the tower is 30° find the height of Tower
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tejasshaha15:
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The height of the tower is 86.5m
\bf\large\underline{Given}
Given
The angle of elevation of a tower , from a point on the ground and at a distance of 150m from its foot, is 30°
\bf\large\underline{To \: Find}
ToFind
The height of the tower
\bf\large\underline{Solution}
Solution
Let us consider the height of the tower be x m
From ‘tan’ function we have :
\sf\bullet \: \: \tan\theta =\dfrac{height}{base}∙tanθ=
base
height
Applying trigonometric ‘tan’ on the given data :
$$\begin{lgathered}\sf\implies \tan30\degree = \dfrac{x}{150m} \\\\ \sf\implies \dfrac{1}{\sqrt{3}}=\dfrac{x}{150m}\\\\ \sf\implies x = \dfrac{150m}{\sqrt{3}} \\\\ \sf\implies x = 50\sqrt{3} m \\\\ \sf\implies x = 86.5m\end{lgathered}$$
Thus , height of the tower correct to one place of decimal is 86.5m
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