Question

the angle of elevation from the top of the tower is 30 degree and the angle of elevation from the foot of the building is 60 degree if the building is 19 m high find the height of the tower
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Answer 1

Solution:

Given:

The angle of elevation from top of the tower=30°

and angle of elevation from the foot of the building=60°

The height of building= 19 m.

Then,

In ∆ BCD

tan angle CBD= tan 60°= CD/BD= 19/BD

or ,

BD= 19/tan 60°= 19/√3

so,BD= 19√3

In ∆ABD,

tan angle ABD= tan30°=AB/BD=AB/19/√3

or,

AB=BD×tan30°= 19/√3×1/√3=19/3=6.33

So,the height of tower (AB)=6.33m

Hope it helps you ❣️☑️