The angle of elevation from the top point of the tower is 38 degree from a point A, south of it and 29 degree from the point B east of it. The distance between A and B is 50 Meters. Find the height of the Tower..?
Answers
Answered by
8
so a^2=500
=> a=10√5=22.36m (approx)
•°• The height of the tower is approximately 22.36m
....Just imagine the situation to visualise how the figure would be....
hope it helps....☺☺
=> a=10√5=22.36m (approx)
•°• The height of the tower is approximately 22.36m
....Just imagine the situation to visualise how the figure would be....
hope it helps....☺☺
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Answered by
7
Answer:22.6 m
Explanation:
Basically what we have to do is, we have to keep in mind to use the pythagoras's formula to find the height that is the height of the tower
So at first we will be finding the length of both the sides or base that is OA and OB and it has to be in terms of h, where we have let OC be
Because we are dealing with all right angled triangle, as it is mentioned SOUTH and EAST
So 90 degree there
So we have 3 right angled triangles COA,COB and AOB
In COA and COB
We are provided with angle only and nothing else
So in there we, use tan Theta formula and we take CO is h
Then using pythagoras's formula we find h
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