Question

The angle of elevation from top of tower from point on ground which is 30m away from foot of tower is 30 degree. Find height of tower

Answer 1

Answer:

17.320 m

Step-by-step explanation:

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

$Tan \theta=\frac{Perpendicular}{Base}$

$Tan30^{\circ}=\frac{AB}{BC}$

$30 \times \frac{1}{\sqrt{3}}=AB$

$17.320=AB$

Hence The height of tower is 17.320 m

Answer 2

Answer:The height of tower is 17.320 m

Step-by-step explanation: