Question

The angle of elevation of a bird from 12 meter above a lake is 30 and the angle of depression of its reflection in the lake is 60 find the distance of the bird from the point of observation

Answer 1

you have to just apply sin 30 = Distance of bird from lake 7divided by distance of bird from the observation point . The answer is 24

Answer 2

Answer:

The actual height of the bird

above the surface of the lake is 48m.

• Let P be the point 36 m above the surface.

• L be the point on the lake(image of bird) at which angle of declination is 60°

• B be the point at which bird is present and angle of inclination is 30°

• Let M be a point on the line joining B and L such that PM is parallel to ground.

• So ML is also 36 m.

•Now, tan 60°= ML/PM

•√3 = 36/PM

• PM = 36/√3

• PM = 12√3

•Now, tan 30° = BM/PM

• 1/√3 = BM /(12√3)

• BM =12

•So total height = BM + ML

= 12 + 36

=48 m

Step-by-step explanation:

here is the image below!!!!!!!!

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