The angle of elevation of a bird from a point 40 metres above a lake is 30° and the angle of depression of its reflection in the lake is 60°. Find the height of the bird.
Answers
Answer:
I am trying to visualise the situation as below. it's not very good but will do the needful.
one thing I would like to add. angle of elevation or angle of depression is always measured with horizontal line.
bird
:
onserver :
|. :. h
|. 40 m :
------------------------------------------------
x :
:
:. h
:
reflection
let the height of the bird from level of Lake be h
depth of the reflection will also be h
let the distance between observer and point on Lake just below bird be x
now
tan 30° = (h-40)/x
1/√3 = (h-40)/x
x = √3(h-40).......(1)
again
tan 60° = (h+40)/x
√3 = (h+40)/x
x= (h+40)/√3.......(2)
from (1) and (2)
√3(h-40) = (h+40)/√3
3(h-40) = h+40
3h - 120 = h + 40
3h - h = 40+120
2h = 160
h = 80 m
Answer:
Step-by-step explanation:
HEY MATE THE ANS IS 80 M . HOPE IT HELPS