Question

The angle of elevation of a bird from a point on the ground is 60°, after 50 seconds flight the
angle of elevation changes to 30°. If the bird is flying at the height of 500f3 m, find the
speed of the bird.
​​

Answer 1

Answer:

Let the height of first plane be AB=4000m and the height of second plane be BC=xm

∠BDC=45

∘

and ∠ADB=60

∘

In △CBD

(i)

y

x

=tan45

∘

=1

⇒x=y

In △ABD,

y

4000

=tan60

∘

=

3

⇒x=y=

3

4000

3

=2306.67m

∴ the vertical distance between two=4000−y=4000−2306.67=1693.33m

solution

Step-by-step explanation:

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