The angle of elevation of a cloud from a point 60 m above the surface of the water of a lake is 30 0 and the angle of depression of its shadow from the same point in water of lake is 60 0 . Find the height of the cloud from the surface of water
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Let AO=H
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30°=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60°=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus,
Height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
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CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30°=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60°=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus,
Height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
HOPE IT HELPS!!!
Pls Mark as Brainliest!!
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